CHEM 361 / Test Bank / Catalysis
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Test Bank — Unit 4

Homogeneous & Heterogeneous Catalysis

Practice problems drawn from Housecroft, Atkins, JD Lee, and others. Select an answer or click "Show Answer" to reveal the explanation.

Homogeneous Catalysis

Questions 1–4
Housecroft & Sharpe, Ch. 26 Housecroft
Q1

What is the key distinction between homogeneous and heterogeneous catalysis, and which statement best summarises their relative advantages?

  • a In homogeneous catalysis the catalyst is in a different phase from the reactants; its main advantage is easy separation from products
  • b In homogeneous catalysis the catalyst is in the same phase as the reactants; it offers high selectivity but is harder to separate from products
  • c In heterogeneous catalysis the catalyst is in the same phase as the reactants; it offers high selectivity and easy recovery
  • d There is no practical difference; the terms refer only to the temperature at which the catalyst operates
Answer: (b)

In homogeneous catalysis the catalyst and reactants occupy the same phase (typically both in solution), which allows every catalytic centre to be accessible and often gives excellent selectivity and mild reaction conditions. The main disadvantage is that separating the dissolved catalyst from the product mixture can be difficult and expensive. Heterogeneous catalysts (solid catalyst, liquid or gas reactants) are easier to recover but may offer lower selectivity.

Housecroft & Sharpe, Ch. 26 Housecroft
Catalytic cycle for hydroformylation
Fig. 26.39 — Catalytic cycle relevant to homogeneous catalysis
Q2

In the hydroformylation (oxo) process, an alkene reacts with CO and H2 in the presence of a cobalt or rhodium catalyst. What is the principal product when propene is used as the substrate?

  • a Propanol
  • b Propanal only
  • c Butanal (n- and iso- isomers), i.e. an aldehyde with one more carbon than the alkene
  • d Butanoic acid
Answer: (c)

Hydroformylation inserts CO into the alkene and then reduces the resulting acyl intermediate with H2, producing an aldehyde with one additional carbon atom. From propene (C3) the products are butanal isomers (C4): the linear n-butanal and the branched iso-butanal. Modern Rh-based catalysts with bulky phosphine ligands strongly favour the linear isomer, which is industrially more valuable.

Atkins & Shriver, Chapter 25 Atkins
Q3

The Wacker process converts ethylene to acetaldehyde using a PdCl2/CuCl2 catalyst system in aqueous solution. What roles do Pd and Cu play in this process?

  • a Pd(II) oxidises ethylene to acetaldehyde and is reduced to Pd(0); Cu(II) reoxidises Pd(0) back to Pd(II) and is itself reoxidised by O2
  • b Cu(II) directly oxidises ethylene; Pd serves only as a spectator ligand
  • c Pd(0) reduces ethylene to ethane; Cu(I) provides the electrons
  • d Both metals act as co-catalysts that simultaneously bind ethylene and insert oxygen
Answer: (a)

In the Wacker process, Pd(II) coordinates ethylene and facilitates nucleophilic attack by water, ultimately producing acetaldehyde while Pd(II) is reduced to Pd(0). The co-catalyst Cu(II) reoxidises Pd(0) back to Pd(II), with Cu(I) being generated in the process. Molecular oxygen from air then reoxidises Cu(I) to Cu(II), completing the catalytic cycle and making the overall process catalytic in both metals.

Housecroft & Sharpe, Ch. 26 Housecroft
Q4

Asymmetric catalysis produces one enantiomer preferentially. How did Noyori and Knowles achieve enantioselective hydrogenation, and why was this work significant?

  • a They used racemic mixtures of Pd catalysts to statistically favour one enantiomer
  • b They employed high-temperature heterogeneous Pt catalysts that naturally produce chiral products
  • c They resolved products by chiral chromatography after a non-selective catalytic step
  • d They used chiral phosphine ligands on Rh catalysts to create an asymmetric environment, achieving >95% ee; this earned the 2001 Nobel Prize
Answer: (d)

Knowles developed the chiral phosphine ligand DIPAMP for Rh-catalysed hydrogenation of dehydroamino acids, enabling industrial production of L-DOPA for treating Parkinson’s disease. Noyori introduced BINAP-Ru catalysts that achieve exceptional enantioselectivity (>99% ee) across a range of substrates. Their work, along with Sharpless’s asymmetric oxidation, earned the 2001 Nobel Prize in Chemistry and transformed pharmaceutical synthesis.

Heterogeneous Catalysis

Questions 5–8
Housecroft & Sharpe, Ch. 26 Housecroft
Industrial catalytic process
Fig. 26.44 — Industrial heterogeneous catalysis
Q5

The Haber–Bosch process is one of the most important industrial reactions ever developed. Which metal catalyst is used and why is it effective for this reaction?

  • a Platinum; it has the highest surface area of any metal catalyst
  • b Iron (promoted with K2O and Al2O3); Fe dissociatively chemisorbs N2 at an intermediate strength — strong enough to break N≡N but weak enough to release NH3
  • c Nickel; it selectively binds nitrogen over hydrogen
  • d Vanadium pentoxide; it provides the necessary redox cycling between V(V) and V(IV)
Answer: (b)

The Haber–Bosch process converts N2 + 3H2 → 2NH3 at ~400–500 °C and 150–300 atm over an iron catalyst promoted with K2O (electronic promoter) and Al2O3 (structural promoter). Iron sits near the top of the volcano plot for N2 dissociation: it binds nitrogen strongly enough to break the triple bond but not so strongly that the resulting surface nitrides cannot be hydrogenated and released as ammonia.

Atkins & Shriver, Chapter 25 Atkins
Q6

Heterogeneous catalysis proceeds through a sequence of elementary steps at the catalyst surface. Which sequence correctly describes these steps?

  • a Dissolution → homogeneous reaction → precipitation
  • b Physisorption → desorption → gas-phase reaction → re-adsorption
  • c Diffusion to surface → adsorption (chemisorption) → surface reaction → desorption of products → diffusion away from surface
  • d Sublimation of catalyst → gas-phase reaction → condensation
Answer: (c)

Heterogeneous catalysis involves five key steps: (1) reactant molecules diffuse to the catalyst surface; (2) they adsorb (typically by chemisorption, forming chemical bonds with surface atoms); (3) the adsorbed species undergo surface reaction, often involving bond breaking and formation between co-adsorbed molecules; (4) product molecules desorb from the surface; (5) products diffuse away. The rate-determining step varies by reaction — for example, N2 dissociation is rate-limiting in the Haber process.

JD Lee, Chapter on Industrial Chemistry JD Lee
Q7

The Fischer–Tropsch process uses a heterogeneous catalyst to convert synthesis gas (CO + H2) into useful products. What does this process primarily produce?

  • a A mixture of hydrocarbons (alkanes, alkenes, and oxygenates) using Fe or Co catalysts — effectively converting coal or natural gas into liquid fuels
  • b Pure methane exclusively, using a Ni catalyst
  • c Ammonia, using an iron catalyst at high pressure
  • d Sulfuric acid, using a vanadium oxide catalyst
Answer: (a)

The Fischer–Tropsch (FT) process converts syngas (CO + H2) over Fe or Co catalysts at 150–350 °C into a distribution of hydrocarbons following the Anderson–Schulz–Flory distribution. Products include straight-chain alkanes, alkenes, alcohols, and waxes. The product selectivity depends on temperature, pressure, H2/CO ratio, and catalyst choice. FT synthesis is central to gas-to-liquids (GTL) technology and was historically used in coal-to-fuel conversion.

Housecroft & Sharpe, Ch. 26 Housecroft
Catalytic converter metals and reactions
Fig. 26.47 — Metals and reactions in catalytic converters
Q8

Automotive three-way catalytic converters use platinum-group metals to treat exhaust gases. Which combination of metals and reactions is correct?

  • a Fe and Cu catalyse reduction of CO2 to CO and oxidation of N2 to NO
  • b Au and Ag catalyse combustion of hydrocarbons only
  • c Ti and V catalyse the decomposition of water in the exhaust stream
  • d Pt, Pd, and Rh catalyse oxidation of CO and hydrocarbons to CO2/H2O, and reduction of NOx to N2
Answer: (d)

A three-way catalytic converter simultaneously performs three reactions: (1) oxidation of CO to CO2, (2) oxidation of unburnt hydrocarbons to CO2 and H2O, and (3) reduction of nitrogen oxides (NOx) to N2. Pt and Pd primarily handle the oxidation reactions, while Rh is particularly effective for NOx reduction. The catalyst operates optimally at the stoichiometric air–fuel ratio, monitored by an oxygen sensor (lambda probe).

Catalyst Design & Green Chemistry

Questions 9–12
Atkins & Shriver, Chapter 25 Atkins
Q9

Catalyst poisoning is a major concern in industrial processes. What is catalyst poisoning, and how does sulfur poison metal catalysts?

  • a Poisoning occurs when the product itself inhibits the catalyst; sulfur is not involved
  • b Poisoning occurs when an impurity binds irreversibly to active sites, blocking reactant access; sulfur chemisorbs very strongly on metals like Pt, Ni, and Fe, deactivating them even at ppm levels
  • c Poisoning refers to the physical disintegration of the catalyst pellet under high temperatures
  • d Poisoning means the catalyst changes oxidation state permanently; sulfur acts as a reductant
Answer: (b)

Catalyst poisoning occurs when a substance (the poison) binds strongly to the active sites of a catalyst, preventing reactant molecules from adsorbing and reacting. Sulfur compounds (H2S, thiophene, etc.) are notorious poisons for transition metal catalysts because sulfur forms very strong M–S bonds with metals like Pt, Ni, and Fe. Even parts-per-million concentrations of sulfur can deactivate a catalyst, which is why industrial feedstocks must be desulfurised (e.g. by hydrodesulfurisation) before entering catalytic reactors.

Housecroft & Sharpe, Ch. 26 Housecroft
Ziegler-Natta polymerisation mechanism
Fig. 26.51 — Mechanism of Ziegler–Natta catalysis
Q10

The Ziegler–Natta catalyst revolutionised polymer chemistry. How does the TiCl4/AlEt3 system polymerise olefins, and what are the roles of each component?

  • a AlEt3 alkylates TiCl4 to form an active Ti–C bond; ethylene then inserts repeatedly into this bond via the Cossee–Arlman mechanism, growing the polymer chain
  • b TiCl4 acts as a Lewis acid to protonate the olefin; AlEt3 provides electrons for reduction
  • c Both components form a radical initiator that triggers free-radical polymerisation of ethylene
  • d AlEt3 polymerises the olefin directly; TiCl4 serves only as a solvent
Answer: (a)

In the Ziegler–Natta system, AlEt3 (the co-catalyst) alkylates TiCl4 at the surface of TiCl3, generating a Ti–C bond at a coordinatively unsaturated Ti centre. The olefin coordinates to the vacant site on Ti and then inserts into the Ti–C bond (the Cossee–Arlman mechanism), extending the chain by two carbons per insertion. This coordination–insertion mechanism produces stereoregular (isotactic or syndiotactic) polyolefins, which was the breakthrough that earned Ziegler and Natta the 1963 Nobel Prize.

JD Lee, Chapter on Green Chemistry JD Lee
Q11

The 12 principles of green chemistry, formulated by Anastas and Warner, guide sustainable chemical practice. Which statement best describes how catalysis relates to these principles?

  • a Catalysis violates green chemistry principles because catalysts are often toxic heavy metals
  • b Catalysis is mentioned in only one of the 12 principles and is considered a minor contributor to sustainability
  • c Catalysis is Principle 9 and underpins several others: it improves atom economy, reduces waste, lowers energy requirements, and enables selective transformations that avoid stoichiometric reagents
  • d Green chemistry discourages catalysis in favour of stoichiometric reagents that produce predictable by-products
Answer: (c)

Principle 9 of green chemistry states: “Catalytic reagents are superior to stoichiometric reagents.” Catalysis is central to green chemistry because a catalyst is used in sub-stoichiometric amounts and regenerated, reducing waste (Principle 1). Catalysts enable milder conditions (lower temperature and pressure), saving energy (Principle 6). They improve selectivity and atom economy (Principle 2), and they often eliminate the need for protecting groups or harsh reagents, reducing the number of synthetic steps and overall environmental impact.

Atkins & Shriver, Chapter 25 Atkins
Porous framework materials as catalyst supports
Fig. 26.56 — Porous materials used as catalyst supports
Q12

Metal–organic frameworks (MOFs) and zeolites are both used as catalyst supports or heterogeneous catalysts. Which comparison is most accurate?

  • a Zeolites are amorphous polymers; MOFs are crystalline metals
  • b MOFs have lower surface areas than zeolites and are therefore less useful
  • c Both are identical in structure, differing only in their colour
  • d Zeolites are crystalline aluminosilicates with fixed pore sizes ideal for shape-selective catalysis; MOFs are tuneable metal–ligand frameworks with ultrahigh surface areas but generally lower thermal stability
Answer: (d)

Zeolites are crystalline microporous aluminosilicates (e.g. ZSM-5, faujasite) with well-defined pore sizes (3–10 Å) that enable shape-selective catalysis — only molecules that fit the pores can react. They are thermally robust (>500 °C) and widely used in petroleum cracking and petrochemistry. MOFs are built from metal ions or clusters linked by organic ligands, offering tuneable pore sizes (up to 50 Å) and surface areas exceeding 7000 m²/g, but they typically decompose at lower temperatures (200–400 °C), limiting their use in high-temperature catalysis.

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Homogeneous & Heterogeneous Catalysis