Practice problems drawn from Housecroft, Atkins, JD Lee, and others. Select an answer or click "Show Answer" to reveal the explanation.
Which of the following correctly lists the major types of structural isomerism found in coordination compounds?
Structural (or constitutional) isomers differ in how atoms are connected. In coordination chemistry, the four principal types are: ionization isomerism (different ions inside vs. outside the coordination sphere), hydrate (solvate) isomerism (water bound as ligand vs. lattice), linkage isomerism (different donor atom from an ambidentate ligand), and coordination isomerism (different distribution of ligands between two metal centres). Geometric and optical isomerism are forms of stereoisomerism, not structural isomerism.
The compounds [Co(NH3)5Br]SO4 and [Co(NH3)5SO4]Br are isomers. What type of isomerism is this, and how would you distinguish them experimentally?
These are ionization isomers — they produce different ions when dissolved in water. [Co(NH3)5Br]SO4 releases free SO42− ions (precipitated by BaCl2 as BaSO4), while [Co(NH3)5SO4]Br releases free Br− ions (precipitated by AgNO3 as AgBr). The key diagnostic is that the counter-ion differs between the two isomers, so simple qualitative tests for the free anion identify each form.
[Cr(H2O)6]Cl3 and [Cr(H2O)5Cl]Cl2·H2O are hydrate isomers. When each is dissolved in water and treated with excess AgNO3, how many moles of AgCl precipitate per mole of complex?
In [Cr(H2O)6]Cl3, all three Cl− ions are outside the coordination sphere as counter-ions, so all three are free to precipitate with AgNO3. In [Cr(H2O)5Cl]Cl2·H2O, one Cl− is bound directly to Cr(III) and is not easily displaced, leaving only two free Cl− ions available for precipitation. This difference in AgCl yield is the classic experimental test for hydrate isomers.
The complex [Co(NH3)5(NO2)]2+ exhibits linkage isomerism. One form has the nitro ligand (N-bound, κN) and the other has the nitrito ligand (O-bound, κO). Using HSAB theory, which form is more thermodynamically stable with Co(III)?
Co(III) is a hard Lewis acid (small, highly charged d6 ion). In the NO2− ligand, the nitrogen lone pair is less electronegative and more polarisable than the oxygen lone pairs, but crucially the N-donor provides stronger σ-donation to the hard Co(III) centre. Experimentally, the nitro (κN) isomer is the thermodynamic product while the nitrito (κO) isomer is the kinetic product. The classic Jørgensen experiment demonstrated the irreversible conversion of the yellow nitrito form to the red-brown nitro form upon standing.
For a square planar complex of the type [Ma2b2] (where a and b are monodentate ligands), how many geometric isomers are possible?
In a square planar [Ma2b2] complex, two distinct geometric isomers exist. In the cis isomer, the two identical ligands (a) occupy adjacent positions (90° apart). In the trans isomer, they occupy opposite positions (180° apart). These isomers are non-superimposable and have different physical and chemical properties — a fact with profound consequences in medicinal chemistry (e.g., cisplatin vs. transplatin).
For an octahedral complex of the type [MA2B2C2] (where A, B, and C are different monodentate ligands, each present twice), how many geometric isomers are possible?
An octahedral [MA2B2C2] complex has 6 geometric isomers. One systematic way to count: first choose which pair is trans — there are three ways to place one pair trans (A trans, B trans, or C trans). For each such choice the remaining four ligands (two pairs) occupy the equatorial plane, where they can be arranged in cis-cis or cis-trans patterns, giving 2 arrangements per trans-pair choice. This yields 3 × 2 = 6 distinct isomers. Some of these isomers may also be chiral.
Cisplatin (cis-[PtCl2(NH3)2]) is a potent anticancer drug, but the trans isomer (transplatin) is clinically inactive. What does this dramatic difference in biological activity tell us about the importance of geometry?
Cisplatin’s anticancer activity depends on its ability to form 1,2-intrastrand cross-links between adjacent guanine bases on the same DNA strand. The cis arrangement of the two labile Cl− ligands (90° apart) provides the correct geometry to bridge two neighbouring guanines. In transplatin, the Cl ligands are 180° apart, making intrastrand cross-linking geometrically impossible. This case powerfully illustrates that geometric isomers, despite having identical composition, can have completely different biological and chemical behaviour.
Can tetrahedral complexes exhibit cis-trans (geometric) isomerism?
In a regular tetrahedron, every pair of vertices subtends the same angle at the centre (109.5°). There is no distinction between “adjacent” and “opposite” positions as there is in square planar or octahedral geometry. Therefore, a tetrahedral [MA2B2] complex has only one possible arrangement — no cis-trans isomerism is possible. Tetrahedral complexes can, however, exhibit optical isomerism if they have four different ligands (i.e., [Mabcd]).
What is the rigorous symmetry criterion for a coordination compound to be optically active (chiral)?
A molecule is chiral (optically active) if and only if it has no improper rotation axis Sn. Since a mirror plane is S1 and an inversion centre is S2, the absence of Sn automatically means no mirror planes and no inversion centre. Note that the concept of an “asymmetric carbon” is specific to organic chemistry; in coordination compounds, chirality arises from the spatial arrangement of ligands around the metal, not from carbon stereocentres.
The complex [Co(en)3]3+ (en = ethylenediamine) exists as two enantiomers designated Δ and Λ. What do these labels describe?
The Δ (delta) and Λ (lambda) labels describe the absolute configuration of tris-chelate octahedral complexes. When viewed along the principal C3 axis, the three chelate rings form a propeller-like arrangement. If this propeller follows a right-handed (clockwise) helix, the configuration is Δ; if left-handed (anticlockwise), it is Λ. These labels specify the spatial arrangement, not the direction of optical rotation — the relationship between absolute configuration and sign of rotation must be determined experimentally or computationally.
Consider the complex [Co(en)2Cl2]+. Can the cis isomer be optically active? What about the trans isomer?
The cis-[Co(en)2Cl2]+ ion belongs to the point group C2, which contains only a C2 axis and no improper rotation elements. It is therefore chiral and exists as Δ and Λ enantiomers. The trans isomer, by contrast, possesses a centre of inversion (i = S2) and a mirror plane, placing it in the C2h point group. The presence of these Sn elements renders it achiral. This is a textbook example showing that geometric isomers can differ in their chirality.
How does optical activity in metal complexes relate to the absence of a plane of symmetry (σ) and an inversion centre (i)?
A mirror plane is equivalent to S1 and an inversion centre to S2. The absence of both is necessary but, strictly, not always sufficient — the complete criterion is the absence of any improper rotation axis Sn. For most coordination compounds encountered in practice, checking for σ and i covers the common cases, but the rigorous test (relevant for groups like S4) requires checking all Sn elements. A molecule lacking all Sn is chiral: it cannot be superimposed on its mirror image and will rotate plane-polarised light.
Isomerism in Coordination Compounds